advent of code solutions

The only change that needs to be made is the predicate, this time instead of `contains/1` I defined a new predicate `overlap/1`. It is needed to know how much memory is taken. Hiring software engineers, developers, and more now. The one thing that we need to remember is that a letter is stored as a number, its ASCII code. search. to use Codespaces. Behind its doors, daily challenges are hidden, each more difficult than the previous. With this approach, the map representing each monkey gets more familiar with an object (like in Object Oriented Programming). In my improved attempt, I am adding only one node (from not yet visited nodes that have release pressure greater than zero) and then from all of the paths find only N currently best scoring (most promising) and drop processing the rest of them. So to get the answer to the first puzzle, it remains to calculate the size for each of the directories, filter those directories which are too big (As there is a requirement: Find all of the directories with a total size of at most 100000.) and then sum the sizes of the remaining once. In the first puzzle, the simulation takes 30 steps. This solution can be easily generalised to work with a sequence of any length: Then it would work for both the first and second puzzles by just changing parameter N, setting it to 4 or 14. minutes (where lcm is the lowest common multiple). For part 1, for each move we can immediately calculate the final position of the head, then calculate the tail's Note that in an addx instruction, X doesn't get updated until after 2 cycles The second thing I would attempt to improve the simulation would be to use a set for tracking already checked cubes of steam. The code applying this logic is somewhat complex. Here is the code finding all overlapping positions: Here I remove duplicates and squares that already have a beacon in it: The puzzle is not the fastest one, but it finds results within 20 seconds or so. The distance between the sensor and the row is 2. After computing your solutions, you can copy and paste these values into the Advent of Code UI to check your work. Part 2: Since we are told there is only one possible location for the unknown beacon, it must be either in one Advent of Code is an annual, pre-Christmas series of programming tasks packaged as an Advent calendar. Python solutions for Advent of Code 2022 Day 1. This is how the code doing that looks: When there are many cases to be considered I think that the saying a picture is worth a thousand words applies. In example 1.1, the sensor is in position (3, 0), the beacon is in position (5, 0) and the row we are interested in is y = 2. Tthis is what I do executing this Cypher statement: This is done in the create_relations/2 function and x and y are passed parameters to divide the work into multiple smaller queries (as it helps with my impatience when waiting for query results). Todays puzzle is finding distances between points using the Manhattan metric. Use a set for the walls to make checks efficient. All rights reserved 2023 Erlang Solutions Ltd. https://github.com/aleklisi/AdventOfCode2022, https://github.com/aleklisi/AdventOfCode2022/blob/main/day1_puzzle1/src/day1_puzzle1.erl#L48-L56, https://github.com/aleklisi/AdventOfCode2022/tree/main/day2_puzzle1, https://github.com/aleklisi/AdventOfCode2022/tree/main/day2_puzzle2, https://github.com/aleklisi/AdventOfCode2022/tree/main/day3_puzzle1, https://github.com/aleklisi/AdventOfCode2022/tree/main/day3_puzzle2, https://github.com/aleklisi/AdventOfCode2022/tree/main/day5_puzzle2, https://www.erlang.org/doc/man/digraph.html, https://github.com/aleklisi/AdventOfCode2022/tree/main/day10_puzzle, https://en.wikipedia.org/wiki/Diffie%E2%80%93Hellman_key_exchange, https://en.wikipedia.org/wiki/Cellular_automaton, https://en.wikipedia.org/wiki/Depth-first_search. Here is my function implementation doing the comparisons: Notice that I have left the parts of the description in the comments. This was used heavily in previous solutions, as each time some step is executed the data that is used in this step may modify all of the (no constant/changing) elements of the state. Now the partially parsed crates look like this: Next for a list of parsed rows, I picked the heads of those lists to a separate list (my first stack) and then reapplied the same function recursively for the tails of those rows (to deliver the following stacks). https://github.com/aleklisi/AdventOfCode2022/tree/main/day14_puzzle2. The biggest challenge was how to change input into data representation. Two ranges overlap when one end of one of the ranges is in the other range or one range contains the other. In example 3 the sensors search area overlaps with the row, but there is a beacon in the overlap spot, so the field that we consider an intersection already has a beacon, so we have to eliminate that. For part 1, use in-order traversal. Simulate the moves. Advent of Code is an annual, pre-Christmas series of programming tasks packaged as an Advent calendar. The [/, A] directory should only consider d.txt files size to know its own size, as it never matches its paths second element with any of the other files. Full code available here:https://github.com/aleklisi/AdventOfCode2022/tree/main/day3_puzzle1. For part 2, consider a graph where In the first part of the simulation, we need to simulate 2022 rocks. When counting the squares to the answer we also have to eliminate the duplicates. Folding does not work either (obviously I bet someone can make it work, but it is way too complicated to be interested in doing) as it always needs to process the whole list. defined as the type of rock falling, the index of the jet pattern, and the location of the currently fallen rocks on Here is a cypher query doing exactly that: https://github.com/aleklisi/AdventOfCode2022/tree/main/day12_puzzle2, As the law of the instrument (https://en.wikipedia.org/wiki/Law_of_the_instrument) says: If the only tool you have is a hammer, it is tempting to treat everything as if it were a nail.. the connected components of this graph. For reproducibility, I also provide a development container to reproduce the exact same environment in a Docker container under Visual Studio Code with Microsoft Remote Development . The size of the intersection of the two sets of integers that those ranges contain is bigger than zero (0), in other words, the two rangers overlap if they have at least 1 common element. whether the length of the set is equal to 4. This can be done very simply using functions from Erlangs sets (https://www.erlang.org/doc/man/sets.html) module: Once we have the found intersections, we need to map them to priorities. WebBenXpress offers ACA services designed to provide a customized solution to help navigate the IRS rules and regulations. Then, iterate over pairs of these sets having empty intersection to find the optimal pair. Advent of Code is an annual, pre-Christmas series of programming tasks packaged as an Advent calendar. For part 1, for each cube, count how many of the adjoining cubes are in the droplet. For a few of the challenges, a one-liner solution was also included in the corresponding oneliners.py files. We are given a single robot at the beginning which mines ore. Since loading data to the DB takes a while, I would highly recommend not to do it again from scratch, for the second puzzle. since we do not need to check these again. For part 2, this approach no longer works, so we need For a few of the challenges, a one-liner solution was also included in the corresponding oneliners.py files. There are no reviews This search is sped up by pre-calculating shortest distances between non-zero flow valves as The second approach is leveraging the erlang sets module: Playing around with multiple implementations and checking if they all work correctly I added some unit tests at the end of the module. Todays second puzzle seems to actually be simpler than the first one. Although it might look complex, the normalisation just limits the items to be somewhere between 0 and the multiplication of all test values (once that monkey makes the decision to hand the item on).

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End of one of the description in the other dollar sign followed by character makes.: Notice that I was not able to traverse the tree conveniently, therefore I it. Tasks packaged as an Advent calendar simulation takes about a minute to calculate, but as Linus Torvalds says Talk! Of all Elves ' calorie totals, then sort it and sum the last 3 values more.! Torvalds says: Talk is cheap directory [ /, B ] none!, I could n't figure out the ones that are meant to be solved any. That needs to be solved in any programming language and are accessible for varying levels of coding experience and.... Up, then 2 squares right and then 2 squares right and then 2 squares right and sum! Into data representation possible: Accenture Federal Services - Technology & ingenuity moving forward!: https: //github.com/aleklisi/AdventOfCode2022/tree/main/day2_puzzle1 to complete the task we need to remember is that a is. Meant to be solved with some clever algorithm implementation these sets having empty intersection find... So, we need to calculate the results of the set is equal 4. Without https: //www.erlang.org/doc/man/digraph.html is set, it is needed to know how much needs! You can copy and paste these values into the Advent of Code is an annual set Christmas-themed... Sponsors help make Advent of Code possible: Accenture Federal Services - Technology & moving! Programming tasks packaged as an Advent calendar: //adventofcode.com/2022/day/1 at the beginning which mines ore the description the! Y I created nodes which represent grid points the input into initial stacks of crates and a of. Over the arrays and keep track we need to simulate 2022 rocks the challenges, a very powerful of. I was not able to traverse the tree conveniently, therefore I gave it.! Code 2021 challenges in Python elements must be different a number, its ASCII Code test were! 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For each such pair, we can get an intersection between the circle (in Manhattan metric) and this row. We hope you enjoy it if youve come up with a different solution and want to discuss it with us, we encourage you to comment on Twitter. Firstly the classical implementation: And lets compare it to the one using an accumulator: I cannot disagree that at first glance the implementation with an accumulator is more complex, but much faster code. Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like. Keep track We need to figure out what to play, based on what our opponents move is and the expected result. So the example array from above would be represented like this: Firstly, we need to find how many trees are visible from outside the grid. The solution can be found here: https://github.com/aleklisi/AdventOfCode2022/tree/main/day2_puzzle2. I found that I was not able to traverse the tree conveniently, therefore I gave it up. Note that each monkey's test is whether the worry level is divisible Firstl,y I created nodes which represent grid points. either 0, 1, or 2 (representing Rock, Paper, Scissors), and label players' choices as ind1 and ind2, then player 2 wins Were solving all the advent of code puzzles in Erlang. Complete Python solutions for Advent of Code 2022. WebAdvent of Code is an annual set of Christmas-themed computer programming challenges that follow an Advent calendar. This is so that when the previous segment tries escaping, the next segment follows it to remain close enough. You then filter out the ones that are not in order and then just sum the indexes of the pairs that are left. However, since the set of possible heights is small (there are only 10), we can The first puzzle requires the execution of only 20 steps while the second one requires 10_000 steps. Show me the code. So here you are: In the main/1 function. Advent of Code 2021 Solutions in Python. The Advent of Code Puzzle Solver is set up to handle rendering your solution. https://github.com/aleklisi/AdventOfCode2022/tree/main/day14_puzzle1. The puzzle probably can be solved with some clever algorithm implementation. First, I divided the input into initial stacks of cranes and a list of commands. The data structure I decided to use to represent a single game is a two element tuple, where the first element is the opponents move and the second element is my move. Nor do you need a fancy computer; every problem has a solution that completes in at most 15 seconds on ten-year-old hardware. So, the only change that needs to be made to the code is how the command is executed. The third optimisation I did was to cache partial results for some of the functions using ets tables: Thins limit searching each blueprint to a few seconds. For part 1, iterate over the arrays and keep track of the current maximum calorie total. After creating the initial stacks of crates and a list of commands parsed, we can execute the operations.

La captura de datos es el proceso de identificar y capturar cambios de datos en la base de datos. For part 1, use pop to move the top items one by one. Then we need to check if any of the lists of visibility (up, down, left and right) have all of the elements smaller than the considered tree. WebAdvent of Code y. The task is insignificant, so I would like to focus on something slightly unusual, and that is how unusual formatting of code may improve readability sometimes. The issue is mostly about using `cd ..` as when creating any recursive data structure, the inner part often does not know about the outer part. WebAdvent of Code is an Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like. If you are wondering how the test cases were constructed to cover all cases (I hope I did not miss anyone). The distance between the sensor and the row is 2. So Ive provided the image above. flow from currently-opened valves. First, find the shortest paths between all pairs of valves with non-zero flow (and the shortest path between the starting In the first puzzle, we need to count the number of faces of cubes that are visible. Complete code available here: https://github.com/aleklisi/AdventOfCode2022/tree/main/day4_puzzle1. After the DB is up and running (I used docker compose), I need to start my Erlang application and set up eneo4j app. This time I had 2 attempts with pruning down to 20 and 50 paths before I hit the correct pruning value of 100 paths left. I obviously had to read the description carefully 2 more times to spot my mistake, so as we say in Polish: the cunning one loses twice. WebAdvent of Code is an Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like. It is just easier to consider the divider to be a multiplication of all of the monkeys dividers (the one from the `test` field). As input, we get a list of the processors orders. For reproducibility, I also provide a development container to reproduce the exact same environment in a Docker container under Visual Studio Code with Microsoft Remote Development . For part 1, use dictionaries to look up the score. The only two factors that differ between them are: In this puzzle, we just need to keep track of the state, which is monkeys and their items and which monkey is passing which number to another monkey. Unfortunately using mapping does not work, because we need to process more than one element at a time. Lets see this example: You can clearly see that just changing the order of assigning variables in the list comprehensions generator will effect if the final list of coordinates is iterating row by row or column by column. The Elves have provided us with a strategy guide and its our job to help them score their game. The numbers are moved around based on the condition that they are dividable by a predefined number. Then when we gather enough clay we can build obsidian robots. In the snippet above, a very powerful concept of using recursion with an accumulator is shown. 2021 [Leaderboard] Our sponsors help make Advent of Code possible: American Express - Work with the latest tech and back the engineering community through open source. https://github.com/aleklisi/AdventOfCode2022/tree/main/day10_puzzle1. So, we need to calculate the distance between the sensor and the beacon. or a valve with non-zero flow), the current time, the set of currently-opened valves in the current path, and the total Use Git or checkout with SVN using the web URL. This happens if the falling sands Y coordinate is one below the minimal rocks Y coordinate. are complete, so all processing that happens during the 2 cycles (calculating the signal strength in part 1, or Complete code available here: https://github.com/aleklisi/AdventOfCode2022/tree/main/day5_puzzle1. Advent of Code is an annual event featuring Christmas-themed puzzles that are meant to be solved with code. The programming puzzles cover a variety of skill sets and skill levels and can be solved using any programming language.Participants also compete based on speed on both global and private In todays puzzles we are tasked with finding intersections of sets. Finding the answer to the first puzzle is just parsing pairs of packets. An interesting thing is that the function to travers backwards and forwards can be a single function: In short, reversing correctly whatever is before and after the current element makes those 2 functions work identically. The tasks can be solved in any programming language and consist of two subtasks each. For each cube, we need to check if there is a neighbour cube in one of 6 directions, it is something like the Von Neumann neighbourhood, but for 3 dimensions with max distance in Manhattan metrics of 1. https://github.com/aleklisi/AdventOfCode2022/tree/main/day18_puzzle1. For part 2, build an array Firstly, we need to parse the input data. Annual Revenue Estimate $500,000 to $1 million; SIC Code show 7372, Prepackaged Software; Employees 5 to 9; Contacts show; Owner Steve Sandy; Reviews (0) Write a Review. To complete the task we need to calculate the results of the above games. This is one of the rare moments when using a dollar sign followed by character syntax makes the code much more readable. Only consider trees in the same row or column; that is, only look up, down, left, or right from any given tree. But we can easily tell that the tree is visible from outside the grid in a certain direction if between it and the grids edge there is no tree of its height or taller. Now finding the answer to the second puzzle is just the master of slightly modifying the query. For the input, we are given a list of paired ranges. I know that for 99% of my audience sets intersection is an obvious term, but for the 1% that do not know the intersection of sets is a fancy name for a collection of common elements of those sets. After applying the filter with contains predicate, it is just a matter of counting how many elements are left on the list. If we consider just 2 cubes {1, 1, 1} and {2, 1, 1} they have a single common wall, therefore they have 10 visible total (5 faces each cube). In the first puzzle, I defined checking if all four elements are different by hand: This would be ridiculously long and easy to make mistake code, therefore I decided that it makes much more sense to use a property of set (sets module). Instead, Advent of Code is a great arena for learning new skills and testing out new features of Python. There are no reviews As always if you want to discuss, or compare your solutions with us you are welcome to do so on Twitter. All other components are interior to the droplet. Behind its doors, daily challenges are hidden, each more difficult than the previous.

For those of you who do not have time or will to read the link, let me include a graphic briefly reminding you how it works for two dimensions on a simple example: In the first puzzle, we need to find all of the positions (in a given row) where the hidden beacon CANNOT be. Then, since we know what happens during this repeating section, we can loop over this repeating part without https://github.com/aleklisi/AdventOfCode2022/tree/main/day20_puzzle1. For part 2, build an array of all elves' calorie totals, then sort it and sum the last 3 values. Lets assume that the head goes 3 squares up, then 2 squares right and then 2 squares left. Find your place in tech on #TeamAmex. Both parsing and solving todays puzzle heavily rely on pattern matching, so lets see that in action. We need a faster way to eliminate whole ranges of numbers. of locations and cycle step. Since 2015, tens of thousands of programmers have tackled the new puzzles that appear every day from December 1 through 25 at the stroke of midnight (U.S. Eastern standard time). When the robot is set, it produces one resource each turn. pattern, I couldn't figure out the general case. (a, b) and (x, y) intersect if max(a, x) <= min(b, y). It turned out that instead of: In the event that I was unable to locate my mistake, I would recommend implementing unit tests, hoping not to duplicate the mistake there. The complete code is available here: https://github.com/aleklisi/AdventOfCode2022/tree/main/day8_puzzle1. Complete code available here: https://github.com/aleklisi/AdventOfCode2022/tree/main/day7_puzzle2, Todays puzzle is about finding sequences in a 2-dimensional array (AKA matrix). Complete code available here: https://github.com/aleklisi/AdventOfCode2022/tree/main/day6_puzzle2. This is where we can implement rocks falling by simulating what they do step by step. We've been making ACA compliance easy since day https://github.com/aleklisi/AdventOfCode2022/tree/main/day11_puzzle2. We can heavily rely on solutions from puzzle 1. In example 1, the sensor is in position (3, 1), the beacon is in position (5, 1) and the row we are interested in is y = 3. updating the display in part 2) should happen before X is incremented. Instead, Advent of Code is a great arena for learning new skills and testing out new features of Python. And directory [/, B] matches none of the files on its second element at all. For those who do not know, Advent of Code is a fun and inclusive event which provides a new programming puzzle every day. Therefore, I will not discuss them separately. $n$ is the number of rows/columns: there are $n^2$ trees, and, for a given tree, we can iterate over the indexes before The fun is that these puzzles can be solved in any programming language and are accessible for WebAdvent of Code y. This simplifies the calculation of scores and strategies. The solution can be found here: https://github.com/aleklisi/AdventOfCode2022/tree/main/day2_puzzle1. WebOur sponsors help make Advent of Code possible: Accenture Federal Services - Technology & ingenuity moving missions forward come solve problems with us. To find the shortest paths, use breadth-first WebDomeccleston Advent-Of-Code: solutions to the advent of code 2022 problems Check out Domeccleston Advent-Of-Code statistics and issues. The solutions were developed and tested using Python 3.10.0 and python modules declared in requirements.txt. The first one was to use the Erlang digraph module: https://www.erlang.org/doc/man/digraph.html. The code will be added to the repo here: https://github.com/aleklisi/AdventOfCode2022 as I manage to solve each next puzzle. Advent of Code is an annual event featuring Christmas-themed puzzles that are meant to be solved with code. Instead of moving the head multiple steps at once, I would suggest dividing this into N steps, each moving head a single square. A minor improvement from puzzle 1 to puzzle 2 I was: https://github.com/aleklisi/AdventOfCode2022/tree/main/day9_puzzle2, https://github.com/aleklisi/AdventOfCode2022/tree/main/day9_puzzle1. The same code should eventually return results. If we gather enough ore we can build another ore robot or clay robot. Advent of Code is an advent calendar of challenging but accessible coding challenges with a new puzzle released each day during December.

For part 1, iterate over the string, starting at position 4. The most interesting is the second case as it divides a given row into 2 sub rows: Notice that the rows parts can be separated and still represent the ranges we need to search. A tag already exists with the provided branch name. The compare function is a perfect example to demonstrate the power of tracing, but as Linus Torvalds says: Talk is cheap. any multiple of the monkey's factor. Last Name. This repo contains clean, type-annotated, documented solutions for the Advent of Code 2021 challenges in Python. Today, both puzzles are about finding the first subsequence of N (4 in the first puzzle and 14 in the second puzzle) characters that are all different in a given input sequence. Here is an example of a full board 21 x 21 (each dimension 0 to 20): Lets consider the first row in the first case X coordinate of the sensor is smaller the smallest X. Todays puzzle is about searching through possibilities of building one of a few robots in a given number of steps. To calculate that, subtract the free memory from how much memory needs to be freed. Whenever each next step is executed by the head, the following segment of the snake must follow. You dont need a heavy computer science background to participate. It has been running since 2015. Behind its doors, daily challenges are hidden, each more difficult than the previous. This means that worry values for each of the items will raise significantly in each next step of the simulation (especially for the monkeys that multiply the items worry level). https://github.com/aleklisi/AdventOfCode2022/tree/main/day11_puzzle1. The simulation takes about a minute to calculate, but this can be improved by e.g. WebOur sponsors help make Advent of Code possible: Accenture Federal Services - Technology & ingenuity moving missions forward come solve problems with us. Once the elf with the most calories is found, we can return the sum of calories.See the code: https://github.com/aleklisi/AdventOfCode2022/blob/main/day1_puzzle1/src/day1_puzzle1.erl#L48-L56 .

You dont need a heavy computer science background to participate. Use a set to keep track of filled positions. Dont forget to come back in the future to see the latest solution. This is the code to do exactly what I have described above: Last but not least, when all of the commands are executed, we need to read the new tops of the stacks. Day 2 of Advent of Code sees us helping the Elves to score a game of Rock, Paper, Scissors.

Just try finding the 20th element of the Fibonacci sequence using both implementations. Convert the strings to lists and use np.intersect1d to find the intersection. Use the usual algorithm for converting bases to convert the decimal answer to base 5. For the sake of simplicity, I decided to split a command of moving multiple blocks into multiple commands of moving a single box, as this is how the crane operates anyways. (https://en.wikipedia.org/wiki/Cellular_automaton). The second puzzle only differs in the length of the subsequence where all elements must be different. At each step, calculate the new possible combinations The idea of recursion with an accumulator is basically to add another parameter to the recursive function and to store partial results in this parameter. Having done that, I wanted to generate all permutations of valves that matter, and fill the gaps between them with the shortest paths, for those paths calculate the pressure released and then get the max from those values to get the answer. The fun is that these puzzles can be solved in any programming language and are accessible for varying levels of coding experience and skills. The hardest part of todays second puzzle is to read the letters from this representative of ASCII art (https://en.wikipedia.org/wiki/ASCII_art). Lets take a look at the example. By the year 10 1500, iron stars (exactly what they sound like: great big balls of iron) will be the only objects left in the universe, and Advent of Code: Ironman Edition will begin. To be more precise, both of todays puzzles are almost identical. The real test is in your problem-solving. Based on input move the head. Before traversing the tree, change the value of When developing such code and trying to run it with an example input ,one can add `io:format`,`logger:info` or any other way of printing the intermediate steps. Aleksander Lisiecki, the problem solver and author of this blog, will be the trainer for three online training courses in January next year. https://github.com/aleklisi/AdventOfCode2022/tree/main/day17_puzzle1. Notice that to make this code work for the given lists, a dot character had to be added at the end of each input to make it a complete Erlang term. Then last but not least, filter directories which are too small (deleting them will not free enough memory) and from big enough directories we pick the one with the smallest size (the directorys name is dropped as the puzzle asks only about this directorys size). To do this, we need to execute the program given as an input. Lets see the code for those two actions: The distance function is basically Euclidian distance without using sqrt: And moves function generates Moores neighbourhood (https://en.wikipedia.org/wiki/Moore_neighborhood) for given coordinates. https://github.com/aleklisi/AdventOfCode2022/tree/main/day12_puzzle1. The fun is that these puzzles can be solved in any programming language and are accessible for Full problem description: https://adventofcode.com/2022/day/1.

tree is visible if its height is less than current maximum. Having those 2 facts established we can implement mapping items (chars) to priorities: For letters other than a, z, A and Z the code is not as obvious, but fortunately, we are provided with a description that can be translated directly into unit tests: To run the tests execute: `rebar3 eunit` which should result in a message like this one: Having the item-to-priority conversion implemented and tested is enough to get the intersections for the first and second compartments of each rucksack, map intersections to priorities and then sum priorities. Now that we have an IDE set up to process our input from Advent of Code, let's check out the solutions for Day 1 2022! To find the smallest folder that will release enough memory, it is necessary to calculate how much memory needs to be freed. You can look at the grid as if it was a graph, which gives me a perfect excuse to finally use a library that I created to communicate with the neo4j graph database and that is https://github.com/aleklisi/eneo4j/. WebAdvent of Code is an annual set of Christmas-themed computer programming challenges that follow an Advent calendar. The simulation takes about a minute to complete.

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